Question

In the figure shown, the relative velocity of link 1 with respect to link 2 is 12 m/s. Link 2 rotates at a constant speed of 120 rpm. The magnitude of Coriolis component of acceleration of link 1 is

• A. $302m/s^2$
• B. $604m/s^2$
• C. $906m/s^2$
• D. $1208m/s^2$

Answer 1

The correct option is A $302m/s^2$

Velocity of link 1 with respect to 2
$V_{1/2}=12$ m/s

$\omega =\frac{2\pi N}{60}\frac{2\pi \times 120}{60}=12.566\text{rad/s}$

$\therefore$ Coriolis component of acceleration
$=2V_{1/2}\omega =2\times 12\times 12.566=302m/s^2$