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V-I Characteristics for a P-N Junction Diode

In the figure...

Question

In the figure shown, what is the current (in ampere) drawn from the battery? You are given
$R_{1} = 15 Ω, R_{2} = 10 Ω, R_{3} = 20 Ω, R_{4} = 5 Ω, R_{5} = 25 Ω, R_{6} = 30 Ω, E = 15 V$

\frac{9}{32}

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\frac{20}{3}

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\frac{7}{18}

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\frac{13}{24}

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Solution

The correct option is A $\frac{9}{32}$
Circuit can be simplified and reduced as :

Series combination of $20 Ω, 5 Ω, 25 Ω$

$= 20 Ω + 5 Ω + 25 Ω = 50 Ω$

Parallel combination of $10 Ω$ and $5 Ω$

$= \frac{10 Ω \times 50 Ω}{10 Ω + 50 Ω}$ $= \frac{25}{3} Ω$

Now, all the three resistances in reduced circuit are connected in series with the battery

$∴ R_{e q} = 15 Ω + \frac{25}{3} Ω + 30 Ω$

$= \frac{45 + 25 + 90}{3}$

$\Rightarrow R_{e q} = \frac{160}{3} Ω$

Given $E = 15 V,$ then

$i = \frac{E}{R_{e q}} = \frac{15 \times 3}{160} = \frac{9}{32} A$ (ohm's law)

Hence, option (c) is correct.

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Similar questions

Q. In the figure shown, what is the current (in

Ampere

) drawn from the battery? You are given:

R_{1} = 15 Ω, R_{2} = 10 Ω, R_{3} = 20 Ω, R_{4} = 5 Ω, R_{5} = 25 Ω, R_{6} = 30 Ω, E = 15 V

Q. In the circuit given,

E = 6.0 V, R_{1} = 100 Ω, R_{2} = R_{3} = 50 Ω

and

R_{4} = 75 Ω

. The equivalent resistance of the circuit

(in Ω)

Q. The potential difference

V_{A} - V_{B}

in the circuit shown is :
Given:

E_{1} = 1.5 V, E_{2} = 2.0 V, E_{3} = 2.5 V

R_{1} = 10 Ω, R_{2} = 20 Ω, R_{3} = 30 Ω

Q. Find the current flowing through the resistance

R_{1}

of the circuit shown in the figure. The resistance are equal to

R_{1} = 10 Ω, R_{2} = 20 Ω

and

R_{3} = 30 Ω

and the potentials of points

1, 2

and

3

are given as

V_{1} = 10 V, V_{2} = 6 V

and

V_{3} = 5 V

Resistances of three resistors are given as R1 = 10 Ω, R2 =20 Ω and R3 =30 Ω. Calculate theeffective resistance when they are connected in series. Also calculate the current flowing whenthe combination is connected to a 6V battery.

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V-I Characteristics for a P-N Junction Diode

Standard XII Physics

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In the figure shown, what is the current (in ampere) drawn from the battery? You are given R1=15 Ω, R2=10 Ω, R3=20 Ω, R4=5 Ω, R5=25 Ω, R6=30 Ω, E=15 V

In the figure shown, what is the current (in ampere) drawn from the battery? You are given
$R_{1} = 15 Ω, R_{2} = 10 Ω, R_{3} = 20 Ω, R_{4} = 5 Ω, R_{5} = 25 Ω, R_{6} = 30 Ω, E = 15 V$