In the figure, the blocks A, B and C of mass m each have acceleration a1, a2 and a3 respectively. F1and F2 are external forces of magnitude 2 mg and mg respectively. Then
A
a1=a2=a3
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B
a1>a3>a2
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C
a1=a1.>a2>a3
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D
a1>a2,a2=a3
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Solution
The correct option is Aa1=a2=a3 equation of motion of the three case are as follows-