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Question

In the figure, the blocks A, B and C of mass m each have acceleration a1, a2 and a3 respectively. F1and F2 are external forces of magnitude 2 mg and mg respectively. Then
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A
a1=a2=a3
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B
a1>a3>a2
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C
a1=a1.>a2>a3
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D
a1>a2,a2=a3
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Solution

The correct option is A a1=a2=a3
equation of motion of the three case are as follows-
CASE A
2mgmg=ma1
a1=g
CASE B
Tmg=ma2
2mgT=2ma2
a2=g3
CASE C
Tmg=ma3
mg+mgT=ma3
a3=g2.


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