In the figure, triangle ABC is similar to triangle EDC : If we have AB = 4 cm, ED = 3 cm, CE = 4.2 cm and CD = 4.8, cm, then the values of CA and CB respectively are

6 cm, 6.6 cm

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4.8 cm, 6.6 cm

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5.4 cm, 6.4 cm

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5.6 cm, 6.4 cm

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Solution

The correct option is D 5.6 cm, 6.4 cm
By property of similar triangle, we have
$\frac{A B}{D E} = \frac{B C}{D C} = \frac{A C}{C E}$
$\frac{4}{3} = \frac{B C}{4.8} = \frac{A C}{4.2}$
$\Rightarrow$ $B C = 6.4$ and $A C = 5.6$
Hence $C A = 5.6 c m, D A = 6.4 c m$

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In the figure, triangle ABC is similar to triangle EDC : If we have AB = 4 cm, ED = 3 cm, CE = 4.2 cm and CD = 4.8, cm, then the values of CA and CB respectively are

The correct option is D 5.6 cm, 6.4 cmBy property of similar triangle, we have ABDE=BCDC=ACCE43=BC4.8=AC4.2⇒ BC=6.4 and AC=5.6Hence CA=5.6cm,DA=6.4cm

The correct option is D 5.6 cm, 6.4 cm
By property of similar triangle, we have
$\frac{A B}{D E} = \frac{B C}{D C} = \frac{A C}{C E}$
$\frac{4}{3} = \frac{B C}{4.8} = \frac{A C}{4.2}$
$\Rightarrow$ $B C = 6.4$ and $A C = 5.6$
Hence $C A = 5.6 c m, D A = 6.4 c m$