In the figures shown, spheres are identical and angle of inclination and height of all the three inclined planes are same. The rough part of the surface is shown in bold line. If three spheres are released from rest at the respective tops and KA,KB and KC are respectively the energies at the bottom of the inclined plane, then.
In the given figure spheres are identical and angle of inclination and height is same. Here KA,KB and KC are the energies at the bottom of the inclined plane. Then
KA=KB>KC