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In the figure...

Question

In the figures shown, spheres are identical and angle of inclination and height of all the three inclined planes are same. The rough part of the surface is shown in bold line. If three spheres are released from rest at the respective tops and $K_{A}, K_{B}$ and $K_{C}$ are respectively the energies at the bottom of the inclined plane, then.

A

K_{A} < K_{B}

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B

K_{A} = K_{B} < K_{C}

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C

K_{A} < K_{B} = K_{C}

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D

K_{A} = K_{B} > K_{C}

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Solution

The correct option is D $K_{A} = K_{B} > K_{C}$
In the given figure spheres are identical and angle of inclination and height is same. Here $K_{A}, K_{B}$ and $K_{C}$ are the energies at the bottom of the inclined plane. Then

$K_{A} = K_{B} > K_{C}$

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