In the following circuit the resistance of wire AB is 10Ω and its length is 1m. Rest of the quantities are given in the diagram. The potential gradient on the wire will be
A
0.08Vm
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B
0.008Vm
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C
0.8Vm
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D
none
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Solution
The correct option is B0.8Vm
Potential gradient depends only on the primary circuit ⇒
voltage drop per unit length of the wire(v)
current in primary circuit = 215+10=225A
voltage drop per unit length of the wire AB⇒v=IRL=225×101