Question

In the following common emitter configuration an n-p-n transistor with current gain $\beta =100$ is used. The output voltage of the amplifier will be :

• A. 10 mV
• B. 0.1 V
• C. 1.0 V
• D. 10 V

Answer 1

The correct option is D 10 V

$\beta =\frac{i_C}{i_B}=100$

$I_C=100\times \frac{10mV}{1k\Omega }=1mA$

$\therefore V_o=I_C\times R_o=1mA\times 10k\Omega =10V$