In the following disintegration 23892U - 20682Pb-number of -particles emitted is

The correct option is A 6The number of alpha particles emitted 238 206/4 = 8 The number of beta particles emitted 82 [92 (8 × 2) ]= 6 When an alpha ...

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Standard X

Physics

Nuclear Fission

In the follow...

Question

In the following disintegration
$_{92}^{238} U ⟶_{82}^{206} P b + . . . . . . .$
number of $β$ -particles emitted is

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Solution

The correct option is A 6
The number of alpha particles emitted
$\frac{238 - 206}{4} = 8$
The number of beta particles emitted
$82 - [92 - (8 \times 2)] = 6$
When an alpha particle is emitted, the atomic number decreases by 2 and the mass number decreases by 4.
When a beta particle is emitted, the atomic number is increased by 1.

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In the following disintegration 23892U⟶20682Pb+.......number of β-particles emitted is

In the following disintegration
$_{92}^{238} U ⟶_{82}^{206} P b + . . . . . . .$
number of $β$ -particles emitted is