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Byju's Answer
Standard XII
Chemistry
Vant Hoff's Equation and Effect of Temperature on Equilibrium Constant
In the follow...
Question
In the following equilibrium
N
2
O
4
(
g
)
⇌
2
N
O
2
(
g
)
N
O
2
(
g
)
is 50% of the total volume. Hence degree of dissociation and van't Hoff factor (i) respectively are:
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Solution
N
2
O
4
⇌
2
N
O
2
1
−
x
2
x
x
=
50
%
=
0.5
=
degree of dissociation
i
=
1
−
x
+
2
x
/
1
=
x
+
1
/
1
=
1.5
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Similar questions
Q.
In the following equilibrium
N
2
O
4
(
g
)
⇌
2
N
O
2
(
g
)
N
O
2
(
g
)
is
501
of the total volume. hence degree of dissociation and vant hoff factor (i) respectively are:
Q.
For the following equilibrium,
N
2
O
4
⇌
2
N
O
2
in gaseous phase,
N
O
2
is 50% of the total volume when equilibrium is set up. Hence, percent of dissociation of
N
2
O
4
is:
Q.
For the equilibrium
N
2
O
4
⇌
2
N
O
2
in gaseous phase,
N
O
2
is
50
%
of the total volume when equilibrium is set up. Hence percent of dissociation of
N
2
O
4
is:
Q.
Gaseous
N
2
O
4
dissociates into gaseous
N
O
2
according to the reaction
N
2
O
4
(
g
)
⇌
2
N
O
2
(
g
)
at 300 K and 1 atm pressure, the degree of dissociation of
N
2
O
4
is 0.2. If one mole of
N
2
O
4
gas is contained in a vessel, then the density of the equilibrium mixture is :
Q.
For the dissociation reaction,
N
2
O
4
⇌
2
N
O
2
(
g
)
, the equilibrium constant
K
p
is 0.120 atm at 298 K and total pressure of system is 2 atm. Calculate the degree of dissociation of
N
2
O
4
.
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