In the following figure, AD and EF are medians. What’s the length of FC?
Since AD is the median, BD = DC. So, CD = 4 cm
Also, since EF is the median, \(DF = CF = \frac{CD}{2} = \frac{4}{2}=2~\text{cm}\)
In the following figure, AB =EF, BC = DE and ∠ B = ∠ E = 900.
Prove that AD =FC.