Question

In the following figure, in $\Delta PQR$, seg RS is the bisector of $\angle PRQ$. If $PS=9,SQ=6,PR=18$, find $QR$.

Answer 1

In $\Delta PQR$, seg is the bisectors of $\angle PQR$.
$\therefore \frac{PR}{QR}=\frac{PS}{SQ}$
$\therefore \frac{18}{QR}=\frac{9}{6}$
$\therefore QR=\frac{18\times 6}{9}=12$
$\therefore QR=12$