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Standard XII

Physics

Resistors in Series and Parallel

In the follow...

Question

In the following figure, the potential difference is shown on $R, L$ & $C$ . The emf of source in $volt$ is

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Solution

The correct option is C $50$
Using the concept of phasor diagram we have:

$V_{n e t} = \sqrt{V_{R}^{2} + (V_{L} - V_{C})^{2}}$

$V_{n e t} = \sqrt{(30)^{2} + (60 - 100)^{2}}$

$V_{n e t} = \sqrt{900 + 1600} = 50 V$

Hence, option $(C)$ is correct.

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In the following figure, the potential difference is shown on R,L & C. The emf of source in volt is

The correct option is C 50Using the concept of phasor diagram we have: Vnet=√V2R+(VL−VC)2 Vnet=√(30)2+(60−100)2 Vnet=√900+1600=50 V Hence, option (C) is correct.

In the following figure, the potential difference is shown on $R, L$ & $C$ . The emf of source in $volt$ is

The correct option is C $50$
Using the concept of phasor diagram we have:

$V_{n e t} = \sqrt{V_{R}^{2} + (V_{L} - V_{C})^{2}}$

$V_{n e t} = \sqrt{(30)^{2} + (60 - 100)^{2}}$

$V_{n e t} = \sqrt{900 + 1600} = 50 V$

Hence, option $(C)$ is correct.