Question

In the following question, two equations numbered I and II are given. Solve both the equations and mark the appropriate option:

I. $16x^2-34x+17.5=0$
II. $3y^2+30y+72=0$

• A. if x > y
• B. if x < y
• C. if x y
• D. if x y
• E. if x = y or relationship between x and y cannot be determined

Answer 1

The correct option is A if x > y

$16x^2-34x+17.5=0$
$\Rightarrow (4x-5)(4x-3.5)=0$
$\Rightarrow x=\frac{5}{4},\frac{7}{8}$
$30y^2+30y+72=0$
$\Rightarrow (3y+12)(y+6)=0$
$\Rightarrow y=-4,-6$
$\therefore x>y$