Question

In the following question, two equations numbered I and II are given. Solve both the equations and mark the appropriate option:
$I.3x^2-19x-14=0II.2y^2+5y+3=0$

• A. 1
• B. 2
• C. 3
• D. 4
• E. $x=y$ or relationship between x and y cannot be determined

Answer 1

The correct option is A 1

$I.3x^2-21x+2x-14=03x(x-7)+2(x-7)=0(3x+2)(x-7)=0\therefore x=7,-\frac{2}{3}II.2y^2+5y+3=02y^2+2y+3y+3=02y(y+1)+3(y+1)=0(2y+3)(y+1)=0\therefore y=-\frac{3}{2},-1\therefore x>y$