Question

In the following question, two equations numbered I and II are given. Solve both the equations and mark the appropriate option:

$I.12x^2+26x-56=0$
$II.6y^2-50y+56=0$

• A. if x > y
• B. if x < y
• C. if x y
• D. if x y
• E. if x = y or relationship between x and y cannot be determined

Answer 1

The correct option is D if x y

$12x^2+26x-56=0$
$\Rightarrow (3x-4)(4x+14)=0$
$\Rightarrow x=\frac{4}{3},-\frac{7}{2}$
$6y^2-50y+56=0$
$\Rightarrow (3y-4)(2y-14)=0$
$\Rightarrow y=\frac{4}{3},7$
$\therefore x\le y$