In the following question, two equations numbered I and II are given. Solve both the equations and mark the appropriate option: I.6x2−7x+2=0 II.6y2+y−2=0
A
x > y
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x y
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
x < y
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x y
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
x = y or the relationship between 'x' & 'y' cannot be determined
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B x y 6x2−7x+2=0(2x−1)(3x−2)=0x=12or236y2+y−2=0(2y−1)(3y+2)=0y=12or−23 Largest value of y = 12 = least value of x So, x≥y.