Question

In the following question, two equations numbered I and II are given. Solve both the equations and mark the appropriate option:

$I.9a^2+18a+5=0$
$II.2b^2+13b+20=0$

• A. a < b
• B. a > b
• C. a b
• D. a b
• E. a = b or relationship between a & b cannot be determined

Answer 1

The correct option is B a > b

$I.9a^2+3a+15a+5=0\Rightarrow (3a+5)(3a+1)=0\Rightarrow a=-\frac{5}{3},-\frac{1}{3}II.2b^2+8b+5b+20=0\Rightarrow (2b+5)(b+4)=0\Rightarrow b=-\frac{5}{2},-4$
Hence, a is always more than b, i.e, a > b.