Question

In the following question, two equations numbered I and II are given. Solve both the equations and mark the appropriate option:
$I.x^2+20x+4=50–25x$
$II.y^2–10y–24=0$

• A. if x > y
• B. if x < y
• C. if x ≥ y
• D. if x ≤ y
• E. if x = y or definite relationship cannot be established between ‘x’ and ‘y’

Answer 1

The correct option is E if x = y or definite relationship cannot be established between ‘x’ and ‘y’

$I.x^2+20x+4=50-25x{x}^2+45x=46x^2+45x=46x^2+45x-46=0x(x+46)-1(x+46)=0(x-1)(x+46)=0\to x=1,-46II.y^2+20x+4=50-25x{y}^2-13y+2y-24=0y(y-1)+2(y-12)=0(y+2)(y-2)=0\to y=-2,12$
Hence, definite relationship cannot be established between x and y.