Question

In the following question, two equations numbered I and II are given. You have to solve both the equations and choose the appropriate answer.

I. $\frac{4}{\sqrt{x}}+\frac{7}{\sqrt{x}}=\sqrt{x}$

II. $y^2-\frac{{\left(11\right)}^{(}\frac{5}{2})}{\sqrt{y}}=0$

• A. if x > y
• B. y > x
• C. x ≤ y
• D. y ≤ x
• E. x = y or the relationship cannot be established

Answer 1

The correct option is E

x = y or the relationship cannot be established

$\begin{array}{ccccccc}I.& 4+7=\sqrt{x}\times \sqrt{x}& x=11.II.& y^2-\frac{{11}^{5/2}}{\sqrt{y}}=0& \Rightarrow y^{2+\frac{1}{2}}={11}^{5/2}& \Rightarrow y^{5/2}={11}^{5/2}& \Rightarrow y=11Clearly,x=y\end{array}$