Question

In the following question, two equations numbered I and II are given. You have to solve both the equations and choose the appropriate answer.

I. $\frac{4}{\sqrt{x}}+\frac{7}{\sqrt{x}}=\sqrt{x}$

II. $y^2-\frac{{\left(11\right)}^{\frac{5}{2}}}{\sqrt{y}}=0$

• A. if x y
• B. if y x
• C. if y x
• D. if x = y or the relationship cannot be established

Answer 1

The correct option is D

if x = y or the relationship cannot be established

$\begin{array}{c}I.4+7=\sqrt{x}\times \sqrt{x},x=11.\\ II.y^2-\frac{{11}^{5/2}}{\sqrt{y}}=0\Rightarrow y^{2+\frac{1}{2}}={11}^{5/2}\Rightarrow y^{5/2}={11}^{5/2}\Rightarrow y=11\\ Clearly,x=y\end{array}$