In the following reaction:
$3 {C l}_{2} + 6 N a O H ⟶ N a C l O_{3} + 5 N a C l + 3 H_{2} O$
The element which loses as well as gains electrons is :

N a

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O

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C l

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none of these

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Solution

The correct option is B $C l$
In the reaction given below:
$3 {C l}_{2} + 6 N a O H ⟶ N a C l O_{3} + 5 N a C l + 3 H_{2} O$
0 +5 -1
$C l_{2}$ undergoes both oxidation and reduction as it is a disproportionation reaction.

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Similar questions

3 {C l}_{2} + 6 N a O H ⟶ 5 N a C l + N a C l O_{3} + 3 H_{2} O

{3 C l}_{2} + 6 N a O H ⟶ 5 N a C l + {N a C l O}_{3} + {3 H}_{2} O, {C l}_{2}

3 C l_{2} + 6 N a O H ⟶ 5 N a C l + N a C l O_{3} + 3 H_{2} O

3 C l_{2} + 6 N a O H \to 5 N a C l + N a C l O_{3} + 3 H_{2} O

3 {C l}_{2} + 6 N a O H ⟶ 5 N a C l + N a C l O_{3} - ------- - + 3 H_{2} O

M

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