In the reaction: ${3 C l}_{2} + 6 N a O H ⟶ 5 N a C l + {N a C l O}_{3} + {3 H}_{2} O, {C l}_{2}$ acts purely as an oxidizing agent.
If true enter 1, else enter 0.
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Solution

The correct option is A 0
In the reaction: ${3 C l}_{2} + 6 N a O H ⟶ 5 N a C l + {N a C l O}_{3} + {3 H}_{2} O, {C l}_{2}$ acts as an oxidizing agent as well as reducing agent. The oxidation number of chlorine changes from 0 (in $C l_{2}$ ) to -1 (in NaCl). Hence, it is reduced and acts as oxidizing agent. The oxidation number of chlorine changes from 0 (in $C l_{2}$ ) to +1 (in NaClO). Thus, chlorine is oxidized and acts as reducing agent.

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3 {C l}_{2} + 6 N a O H ⟶ 5 N a C l + N a C l O_{3} + 3 H_{2} O

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