Question

In the following reaction,
$3Fe$ + $4H_{2}O$ $\to$ $F{e}_3{O}_4$ + $d{H}_2$.
Find the value of d.

• A. 2
• B. 3
• C. 4
• D. 1

Answer 1

The correct option is C

4

$3Fe$ + $4H_{2}O$ $\to$ $F{e}_3{O}_4$ + $d{H}_2$

A balanced chemical equation has equal number of atoms of each element on both sides.

$\begin{array}{ccc}\text{Name of the atom}& \text{No. of atom in the reactant}& \text{No. of atoms in product}\\ \text{Iron}& 3& 3\\ \text{Hydrogen}& 8& 8\\ \text{Oxygen}& 4& 4\end{array}$

Thus, the value of d on reactant side will be 4 to have the same number of atoms ( 8 atoms of hydrogen) on reactant and product side