In the following reaction, how is the rate of appearance of product related to the rate of disappearance of the reactant?
$B r O_{3}^{-} (a q) + 5 B r^{- 1} (a q) + 6 H^{+} \to 3 B r_{2} (l) + 2 H_{2} O (l)$

\frac{d [B r_{2}]}{d t} = - \frac{d [B r^{-}]}{d t}

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\frac{d [B r_{2}]}{d t} = \frac{3}{5} \frac{d [B r^{-}]}{d t}

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\frac{d [B r_{2}]}{d t} = - \frac{3}{5} \frac{d [B r^{-}]}{d t}

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\frac{d [B r_{2}]}{d t} = - \frac{5}{3} \frac{d [B r^{-}]}{d t}

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Solution

The correct option is C $\frac{d [B r_{2}]}{d t} = - \frac{3}{5} \frac{d [B r^{-}]}{d t}$
$\frac{1}{3} \frac{d [B r_{2}]}{d t} = - \frac{1}{5} \frac{d [B r^{-}]}{d t}$

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Similar questions

B r O_{3}^{-} (a q) + 5 B r^{- 1} (a q) + 6 H^{+} \to 3 B r_{2} (l) + 2 H_{2} O (l)

B r O_{3 (a q)}^{-} + 5 B r_{(a q)}^{-} + 6 H_{(a q)}^{+} \to 3 B r_{2 (l)} + 3 H_{2} O_{(l)}

B r_{2}

{B r}^{-}

B r O^{3 -} (a q) + 5 B r^{-} (a q) + 6 H^{+} \to 3 B r_{2} (l) + 3 H_{2} O (l)

{B r O_{3}}^{-} (a q .) + 5 {B r}^{-} (a q .) + 6 H^{+} (a q .) ⟶ 3 {B r}_{2} (l) + 3 H_{2} O (l)

({B r}_{2})

B r O_{3}^{-} (a q) + 5 B r^{- 1} (a q) + 6 H^{+} \to 3 B r_{2} (l) + 2 H_{2} O (l)

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