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Question

In the following reaction:
P4(s)+OH(aq)PH3(g)+H2PO2(aq)
Calculate the stoichiometric coefficient of OH and H2O respectively present in a balanced equation in a basic medium?

A
3H2O, 3OH
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B
6H2O, 6OH
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C
3H2O, 6OH
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D
6H2O, 3OH
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Solution

The correct option is A 3H2O, 3OH
0P4(s)+OH(aq)3P+1H3(g)++1H2+1P2O2(aq)

Total decrease in O.N of P4 in PH3=12.
Total increase in O.N of P4 in H2PO2=1×4=4
To balance increase and decrease in O.N, multiply PH3 by 1 and H2PO2 by 3.
P4(s)+OH(aq)PH3(g)+3H2PO2(aq)
To balance O atoms, we have to multiply OH by 6, we get
P4(s)+6OH(aq)PH3(g)+3H2PO2(aq)
To balance H atoms
P4(s)+6OH+3H2OPH3(g)+3H2PO2(aq)+3OH
P4+3OH+3H2OPH3(g)+3H2PO2(aq)

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