Question

In the following Reaction, which substance is oxidised and reduced?
$I_2+NaOH\to I{O}_3+NaI+3H_{2}O$

• A. $I_2,NaOH$
• B. $NaOH,I_2$
• C. $I_2,I_2$
• D. NaOH, NaOH

Answer 1

The correct option is C $I_2,I_2$

$\stackrel{\left(0\right)}{I_2+NaOH}\to \stackrel{(+5)}{NaI{O}_3}+NaI+3H_{2}O$
We can clearly see that $I_2$ is itself oxidised
as well as reduced (disproprtionation).