In the following reactions, $Z n O$ is respectively acting as a/an:
(a) $Z n O + N a_{2} O \to N a_{2} Z n O_{2}$
(b) $Z n O + C O_{2} \to Z n C O_{3}$

Base and base

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Acid and acid

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Acid and base

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Base and acid

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Solution

The correct option is C Acid and base
$Z n O + N a_{2} O \to N a_{2} Z n O_{2}$

Sodium oxide $(N a_{2} O)$
is basic in nature according to the following equation:

$N a_{2} O + H_{2} O$ $\to$ $2 N a O H$
$B a s e$

Compounds that react with a base to produce a neutral salt are acids and thus in this case $Z n O$ behavies as an acid.

$Z n O + C O_{2} \to Z n C O_{3}$

Carbon dioxide is acidic in nature according to the following equation:

$C O_{2} + H_{2} O$ $\to$ $H_{2} C O_{3}$
$a c i d$

Compounds that react with an acid to produce a neutral salt are bases and thus in this case $Z n O$ behavies as a base.

Suggest Corrections

Similar questions

Z n O

Z n O + {N a}_{2} O ⟶ {N a}_{2} Z n O_{2}

Z n O + C O_{2} ⟶ Z n C O_{3}

(a) Z n O + N a_{2} O \to N a_{2} Z n O_{2}

(b) Z n O + C O_{2} \to Z n C O_{3}

Z n C O_{3} ⟶ Z n O + C O_{2}

Z n C O_{3 (s)} Δ - \to

Z n O_{(s)} + C_{(s)} Δ - \to

M n O_{2 (s)} + A l_{(s)} Δ - \to

Z n S_{(s)} + O_{2 (g)} Δ - \to

H g S + O_{2} (g) Δ - \to

{C O}_{2}

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