Question

In the following table pass percentage of three schools from the year $2001$ to the year $2006$ are given. Which school students performance is more consistent?

	$2001$	$2002$	$2003$	$2004$	$2005$	$2006$
School (X)	$80$	$89$	$79$	$83$	$84$	$65$
School (Y)	$92$	$94$	$76$	$75$	$80$	$63$
School (Z)	$93$	$97$	$67$	$63$	$70$	$85$

• A. X
• B. Y
• C. Z
• D. X and Y

Answer 1

The correct option is D X and Y

Average of $x=\frac{80+89+79+83+84+65}{6}=\frac{480}{6}=80$

Average of $y=\frac{92+94+76+75+80+63}{6}=\frac{480}{6}=80$

Average of $z=\frac{93+97+67+63+70+85}{6}=79.16$

Average of x and y are equal and more than z.

So,their performance is consistent.