Question

In the following transistor amplifier circuit $\beta =50.V_{CE}$ of the transistor is

• A. 4 V
• B. 6 V
• C. 10 V
• D. 8 V

Answer 1

The correct option is B 6 V

Here,

Amplification factor, $\beta =50$

Collector resisteance. $R_c=2k\Omega$

Base resistance, $R_b=245k\Omega$

Input voltage, $V_i=10V$

Therefore, voltage gain-

$V_g=\beta \times \frac{R_c}{R_b}\times V_i$

$V_g=50\times \frac{2}{245}\times 10\approx 4\text{Volt}$

So, output voltage is, $V=V_i-V_g=10-4=6\text{Volt}$