In the formation of $N a C l$ , chlorine one electron and sodium one electron to attain noble gas configuration.

loses, gains

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gains, loses

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loses, loses

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gains, gains

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Solution

The correct option is B gains, loses
Sodium loses 1 electron because by losing 1 electron it attains noble gas configuration which is stable like neon
and Chlorine gain one electron because by accepting it also attain stable gas configuration like Argon

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Similar questions

Q. During the formation of sodium chloride, sodium transfers one electron to chlorine to attain the configuration of which noble gas?

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Elements try to become stable by attaining inert gas configuration. In the ionic compound sodium chloride (NaCl), sodium and chlorine attain stability by losing and gaining an electron respectively. Identify the correct options assuming the above situation.

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Q. Assertion :Octet rule is obeyed in the formation of sodium chloride. Reason: According to octet rule, the sodium atom which has only single electron in outermost shell , looses the electron to get a stable configuration like Ne gas, while the chlorine gas with 7 valence electrons gains an electron from the Na atom to obtain an stable configuration like Ar gas.

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In the formation of NaCl, chlorine ________ one electron and sodium ________ one electron to attain noble gas configuration.

The correct option is B gains, losesSodium loses 1 electron because by losing 1 electron it attains noble gas configuration which is stable like neonand Chlorine gain one electron because by accepting it also attain stable gas configuration like Argon

In the formation of $N a C l$ , chlorine one electron and sodium one electron to attain noble gas configuration.

The correct option is B gains, loses
Sodium loses 1 electron because by losing 1 electron it attains noble gas configuration which is stable like neon
and Chlorine gain one electron because by accepting it also attain stable gas configuration like Argon