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Arrhenius Equation

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Question

In the formation of sulphur trioxide by the contact process. $2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{2} (g)$ The rate of reaction is expressed as $- \frac{d (O_{2})}{d t} = 2.5 \times 10^{- 4} m o l L^{- 1} s^{- 1}$ The rate of disappearance of $(S O_{2})$ will be:

A

5.0 \times 10^{- 4} m o l L^{- 1} s^{- 1}

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B

- 2.25 \times 10^{- 4} m o l L^{- 1} s^{- 1}

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C

3.75 \times 10^{- 4} m o l L^{- 1} s^{- 1}

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D

50.0 \times 10^{- 4} m o l L^{- 1} s^{- 1}

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Solution

The correct option is B $5.0 \times 10^{- 4} m o l L^{- 1} s^{- 1}$
$2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{2} (g)$
$R a t e = \frac{- d [S O_{2}]}{2 d t} = \frac{- d [O_{2}]}{d t}$
$∴ = \frac{- d [S O_{2}]}{d t} = 2 \times \frac{- d [O_{2}]}{d t}$
$= 2 \times 2 / 5 \times 10^{- 4}$
$= 5.0 \times 10^{- 4} m o l^{- 4} m o l^{- 1} L^{- 1} s^{- 1}$

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