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Standard XII

Physics

Dimensional Analysis

In the formul...

Question

In the formula : y = a sin ( at - b), where y - position, t - time and A, a, b are constants. What will be the dimensional formula of $\frac{b}{a}$ ?

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L^{- 1}

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T^{- 1}

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Solution

The correct option is A T
Dimensions of at=Dimension of b
$[a] [t] = [b] \frac{b}{a} = t = T$

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In the formula : y = a sin ( at - b), where y - position, t - time and A, a, b are constants. What will be the dimensional formula of ba?

The correct option is A TDimensions of at=Dimension of b[a][t]=[b]ba=t=T

In the formula : y = a sin ( at - b), where y - position, t - time and A, a, b are constants. What will be the dimensional formula of $\frac{b}{a}$ ?

The correct option is A T
Dimensions of at=Dimension of b
$[a] [t] = [b] \frac{b}{a} = t = T$