Question

In the given circuit all diodes are ideal. The current through battery (shown in figure) is

• A. $2A$
• B. $1A$
• C. $3A$
• D. None

Answer 1

The correct option is A $2A$

Diode $D_1$ works as a reverse bias and diode $D_2$ works as a forward bias .
So, the circuit is simplified as the series connection of two sets of the $3\Omega$ and $2\Omega$ resistances.

The equivalent resistance is:
$R_{eq}=2+3+3+2=10\Omega$

Now, the current flowing through the circuit is:
$I=\frac{V}{R_{eq}}=\frac{20}{10}=2A$