In the given circuit diagram the ratio of potential difference across $3$ ohm and $4$ ohm resistance is $\frac{3}{4}$ . The unknown resistance $R$ is:-

8.0 ohm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2.0 ohm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4.5 ohm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7.0 ohm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $8.0 ohm$

Potential difference across $= 3 Ω$ $4 Ω$
resistance $= \frac{3}{4}$
Using wheat stone bridge method we get,
$\frac{5}{6} = \frac{4}{R}$
or, $R = \frac{4 \times 6}{5} = \frac{24}{5} = \frac{40}{5} = 8 Ω$

Suggest Corrections

Similar questions

Q. In the given circuit diagram the ratio of potential ifference across

3

ohm and

4

ohm resistance is

3 / 4

The inkmown resistance R is.

Q. A resistance of

3 o h m s

is connected in series with another resistance of

5 o h m s

. A potential difference of

6

volts is applied across the combination. Calculate the current through the circuit and potential difference across the

3 o h m

resistance.

Q. A resistor of 4-ohm resistance and an electric lamp of 20-ohm resistance are connected in series across a 6-volt battery. Draw a labelled circuit diagram by using the symbols for ohm and volt. Calculate:
(a) total resistance of the circuit.
(b) current flowing through the circuit.
(c) potential difference across the resistor.
(d) potential difference across the electric lamp.

In the circuit diagram given below. Find

(i) Total resistance of the circuit

(ii) Total current flowing in the circuit

(iii) Potential difference across $R_{1}$

4. Define one ohm.

5. Define one ampere of current. [5 MARKS]

Q. Two resistance 3 ohm and 2 ohm are in parallel connection and a potential difference of 12 V is applied across them.Find
a) The equivalent resistance of the parallel combinations.
b) The circuit current and
c) The branch currents.

Join BYJU'S Learning Program

In the given circuit diagram the ratio of potential difference across 3 ohm and 4 ohm resistance is 34. The unknown resistance R is:-

The correct option is A 8.0 ohmPotential difference across =3Ω 4Ωresistance =34Using wheat stone bridge method we get,56=4Ror, R=4×65=245=405=8Ω

In the given circuit diagram the ratio of potential difference across $3$ ohm and $4$ ohm resistance is $\frac{3}{4}$ . The unknown resistance $R$ is:-

The correct option is A $8.0 ohm$

Potential difference across $= 3 Ω$ $4 Ω$
resistance $= \frac{3}{4}$
Using wheat stone bridge method we get,
$\frac{5}{6} = \frac{4}{R}$
or, $R = \frac{4 \times 6}{5} = \frac{24}{5} = \frac{40}{5} = 8 Ω$