In the given circuit diagram the ratio of potential ifference across $3$ ohm and $4$ ohm resistance is $3 / 4$ The inkmown resistance R is.

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Solution

$R 1 = 3 o h m R 2 = 4 o h m, R 3 = 6 o h m$

As the resistors are connected in parallel

$1 / R t o t a l = 1 / 3 + 1 / 4 + 1 / 6$

$1 / R t o t a l = (4 + 3 + 2) / 12$

$1 / R t o t a l = 9 / 12$

$R t o t a l = 12 / 9$

$R t o t a l = 4 / 3 o h m$

Total current $= V o l t a g e / R t o t a l$

$I t o t a l = 2 / (4 / 3)$

$I t o t a l = 6 / 4$

$I t o t a l = 3 / 2 A m p e r e$

For resistance in the parallel ,voltage across each resistor is same and total current is sum of current through each resistor.

Current through $R 1 = V / R 1 = 2 / 3 A m p e r e$

Current through $R 1 = V / R 2 = 2 / 4 = 1 / 2 A m p e r e$

Current through $R 1 = V / R 3 = 2 / 6 = 1 / 3 A m p e r e$

Total current is $3 / 2 A m p e r e$

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In the given circuit diagram the ratio of potential ifference across 3 ohm and 4 ohm resistance is 3/4 The inkmown resistance R is.

In the given circuit diagram the ratio of potential ifference across $3$ ohm and $4$ ohm resistance is $3 / 4$ The inkmown resistance R is.