wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the given circuit, in the steady state condition, the potential drop across the capacitor must be-



A
2V3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
V3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
V2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C V3
In the steady-state condition, no current flows through the capacitor C i.e., along the branch BE



Using KVL to the closed mesh ACDFA,

2V2IRIRV=0

V=3IR

I=V3R

Using KVL to the mesh BCDEB,

2V2IR+qCV=0

qC=V3 (I=V3R)

|ΔV|=V3

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (C) is the correct answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon