In the given circuit, peak voltage across the resistor and capacitor are 6V and 8V. At an instant when voltage across capacitor is 4V in magnitude,
A
Voltage across resistance is −3√3V
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Voltage across resistance is 3√3V
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Peak source voltage is 5√3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Current in circuit is ahead of source voltage
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct options are A Voltage across resistance is −3√3V B Voltage across resistance is 3√3V D Current in circuit is ahead of source voltage VR=VRmaxsin(ωt+θ)=6sin(ωt+θ) VC=−VCmaxcos(ωt+θ)=−8cos(ωt+θ) At an instant, voltage across the capacitor is 4V ⇒−8cos(ωt+53∘)=4cos(ωt+53)=−12sin(ωt+53)=±√32⇒VR=6sin(ωt+53)=±6×√32=±3√3 Vsourcemax=√V2Rmax+V2Cmax = 10V In an RC circuit, current always leads voltage.