    Question

# In the given circuit, peak voltage across the resistor and capacitor are 6V and 8V. At an instant when voltage across capacitor is 4V in magnitude, A
Voltage across resistance is 33 V
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B
Voltage across resistance is 33 V
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C
Peak source voltage is 53
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D
Current in circuit is ahead of source voltage
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Solution

## The correct option is D Current in circuit is ahead of source voltage VR=VRmaxsin(ωt+θ)=6sin(ωt+θ) VC=−VCmaxcos(ωt+θ)=−8cos(ωt+θ) At an instant, voltage across the capacitor is 4V ⇒−8cos(ωt+53∘)=4cos(ωt+53)=−12sin(ωt+53)=±√32⇒VR=6sin(ωt+53)=±6×√32=±3√3 Vsource max=√V2Rmax+V2Cmax = 10V In an RC circuit, current always leads voltage.  Suggest Corrections  0      Similar questions  Explore more