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Question

In the given circuit, superposition is applied. When V2 is set to 0 V, the current I2 is -6 A. When V1 is set to 0 V, the current I1 is +6 A. Current I3 (in A) when both sources are applied will be (up to two decimal places)
https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1159045/original_25.a1.png


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Solution

The correct option is A 1

Case I:
https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1159046/original_26.a1.png
I2=6A

Apply current division and KCL we get

I3=2A

Case II:
https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1159047/original_27.a1.png
I1=6A

Apply current division we get

I′′3=3A

I3=I3+I′′3=2A+3A=1A


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