In the given circuit the mesh current $I_{1}, I_{2} a n d I_{3}$ are

I_{1} = 1 A, I_{2} = 2 A a n d I_{3} = 3 A

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I_{1} = 2 A, I_{2} = 3 A a n d I_{3} = 4 A

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I_{1} = 3 A, I_{2} = 4 A a n d I_{3} = 5 A

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I_{1} = 4 A, I_{2} = 5 A a n d I_{3} = 6 A

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Solution

The correct option is A $I_{1} = 1 A, I_{2} = 2 A a n d I_{3} = 3 A$

$8 I_{1} - 6 I_{2} + 2 I_{3} - I_{2} = 0$ .....(i)

$I_{3} - I_{1} = 2 A$ .....(ii)

$- 6 I_{1} + 7 I_{2} - I_{3} = 5$ .....(iii)

By solving above equations,

$I_{1} = 1 A, I_{2} = 2 A a n d I_{3} = 3 A$

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