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Question

In the given circuit the potential difference across the 4.5μF capacitor is


A
83 V
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B
4 V
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C
6 V
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D
8 V
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Solution

The correct option is D 8 V
C=9×4.513.5μF or C=3 μF
Q=CV=3×12 μC=36 μC
Potential difference across 4.5 μF
=364.5 V=8 V

Time saving solution
V1V2=C2C1=94.5=21
V1+V2=12
V1=8 V


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