Question

In the given circuit, the potential difference between $A$ and $B$ is $18V$ and charges on $2\mu F$ capacitor is $24\mu C$. The value of $C$ is:

• A. $1\mu F$
• B. $2\mu F$
• C. $3\mu F$
• D. $4\mu F$

Answer 1

The correct option is A $1\mu F$

Voltage across $2\mu F$capacitor is $\frac{24}{2}=12V$

So, voltage across $6\mu F$ capacitor is $18-12=6V$

Hence, charge on $6\mu F$ capacitor$6\times 6=36\mu C$

So, charge on C capacitor $=36-24=12\mu C$

The value of C is $C=\frac{12}{12}=1\mu F$