Question

In the given circuit, the potential drop across the capacitor must be

• A. V
• B. V/2
• C. V/3
• D. 2V/3

Answer 1

The correct option is C

V/3

Travelling along the loop BCDEFGB

$IR+V-2V+2RI=OV=3IR\Rightarrow I=\frac{V}{3R}{\text{The potential drop across}}^{\prime }{C}^{\prime }{V}_A-V_B=IR+V-V=IR=\frac{V}{3R}\times R=\frac{V}{3}$