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Question

In the given circuit, the potential drop across the capacitor must be


A

V

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B

V/2

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C

V/3

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D

2V/3

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Solution

The correct option is C

V/3


Travelling along the loop BCDEFGB

IR+V2V+2RI=OV=3IRI=V3RThe potential drop across CVAVB=IR+VV=IR=V3R×R=V3


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