Question

In the given circuit the readings of the voltmeter $V_1$ and the ammeter $A$ are:

• A. 220 V, 2.2 A
• B. 110 V; 1.1A
• C. 220 V, 1.1 A
• D. 110 V; 2.2 A

Answer 1

Answer: (A)

220 V, 2.2 A

$w=100\pi \Omega$

we observe that $w^2=\frac{1}{LC}$

i.e. this frequency is resonance frequency
all the voltage drop across resistor.

$\therefore v_1=220V$

and $i=\frac{V_1}{R}$

$=\frac{220}{100}$

$=2.2A$