Question

In the given circuit with steady current the potential drop across the capacitor must be

• A. V
• B. V/2
• C. V/3
• D. 2V/3

Answer 1

The correct option is C V/3

In the steady state no current flows in the branch containing the capacitor .Thus the current say l flows in the branches containing R and 2R. Applying Kirchoff's second rule to the loop abcdefa
2V-I(2R)-IR-V=0
$l=\frac{V}{3R}$
Potential drop across capacitor =2V-V-l(2R)=$V-\frac{v}{3R}\times 2R$
$=V-\frac{2v}{3}=\frac{v}{3}$