Question

In the given common emitter configuration an npn transistor with current gain $\beta =100$ is used. The output voltage of the amplifier will be:

• A. $10mV$
• B. $0.1V$
• C. $1.0V$
• D. $10V$

Answer 1

The correct option is C $1.0V$

$\beta =\frac{I_c}{I_b}$
Here, $I_c=\frac{V}{10\times {10}^3}=\frac{V}{{10}^4}$
$I_b=\frac{1\times {10}^{-3}}{10\times {10}^3}={10}^{-6}$; $\beta =100$
Now $100=\frac{I_c}{I_b}=\frac{V}{{10}^4}\times {10}^{-6}$
$V=100\times {10}^4\times {10}^{-6}=1V$