Question

In the given figure, $a=15m/s^2$ represents the total acceleration of a particle moving in the clockwise direction in a circle of radius $R$=$2.5m$ at a given instant of time. The speed of the particle is

Answer 1

From the diagram

$a\cos 30°=a_c=\frac{v^2}{R}$

where $a_c$ is centripetal acceleration

$\therefore 15\times \frac{\sqrt{3}}{2}=\frac{v^2}{2.5}\Rightarrow v^2=15\times 2.5\times \frac{\sqrt{3}}{2}\Rightarrow v=5.69m/s$