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Question

In the given figure, a 3.50 g bullet is fired horizontally at two blocks at rest on a frictionless table.The bullet passes through block 1 (mass 1.20 kg) and embeds itself in block 2 (mass 1.80 kg). The blocks end up with speeds v1=0.630 m/s and v2=1.40 m/s (Fig b). Neglecting the material removed from block 1 by the bullet, then

A
the speed of the bullet as it leaves the block 1 is 720 m/s
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B
the speed of the bullet as it leaves the block 1 is 360 m/s
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C
the speed of the bullet as it enters the block 1 is 936 m/s
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D
the speed of the bullet as it enters the block 1 is 1355 m/s
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Solution

The correct option is C the speed of the bullet as it enters the block 1 is 936 m/s
Given that
mass of bullet (m1)3.50 g=0.0035 kg
mass of block 1 (m1)=1.20 kg
mass of block 2 (m2)=1.80 kg
v1=0.630 m/s
v2=1.40 m/s
Applying momentum conservation just before the bullet strikes the second block to the situation where the bullet is embedded within the block.
(0.0035 kg)v=(1.8 kg)×(1.4 m/s)
v=1.8×1.40.0035
v=720 m/s
Again apply momentum conservation to relate the situation just before the bullet strikes the first block to the instant it has passed through it .
(0.0035 kg)v0=(1.2 kg)(0.630 m/s)+(0.0035 kg×720 m/s)
v0=936 m/s
Hence, option a and c are correct

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