Question

In the given figure, AB || CD, ∠ABO = 60° and ∠CDO = 40°. Then, find ∠BOD.

Answer 1

$\begin{array}{l}\\ \angle \text{ABO}={60}^{{}^0}\\ \angle {\text{CDO =40}}^0\\ \angle \text{ABO}=\angle \text{BOC}\left[\text{alternate angles}\right]\\ {\text{=60}}^0\\ \angle \text{CDO}=\angle \text{DOC}={40}^0\left[\text{alternate angles}\right]\\ \angle \text{BOD}=\angle \text{BOC}+\angle \text{DOC}={60}^0+{40}^0={100}^0\\ \end{array}$