In the given figure, AB || CD. If ∠EAB = 50° and ∠ECD = 60°, then ∠AEB = _____.
AB ∥ CD and BC is transversal.
∴ ∠ABE = ∠ECD = 60°
[Alternate interior angles]
In ∆ABE, we have:
∠EAB + ∠ABE + ∠AEB = 180°
[Angle sum property of a triangle]
⇒ 50° + 60° + ∠AEB = 180°
⇒ ∠AEB = 70°